Question

bases of triangle is 9 and height is 5.base of another triangle is 10 and height. is 6.find the ratio of areas of these triangles.​

Answer 1

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given: BC = 9, AB = 5, PQ = 6 and QR = 10.

$\huge \bold{\frac{Area (\triangle \: ABC)}{ Area(\triangle \:PQR)}}$

$\huge \bold{ = \frac{ \frac{1}{2} \times \: AC \times BC}{ \frac{1}{2} \times \: PQ \times PR } }$

$\huge \bold{ = \frac{ \frac{1}{2} \times \: 5\times 9}{ \frac{1}{2} \times \: 6\times 10 } }$

$\huge \bold{ = \frac{3}{4} }$

Hence, Ratio of Area of △ABC : Area of △PQR = 3: 4.