Question

Basic algebra solve guys.....

Answer 1

squaring on both sides
$6 - 4x - {x}^{2} = {(x + 4)}^{2} \\ 6 - 4x - {x}^{2} = {x}^{2} + 8x + 16 \\ 2 {x}^{2} + 12x + 10 = 0 \\ {x}^{2} + 6x + 5 = 0 \\ {x}^{2} + 5x + x + 5 = 0 \\ x(x + 5) + 1(x + 5) = 0 \\ (x + 5)(x + 1) = 0 \\ x = - 5 \\ x = - 1$