Question

basic numaracy for class 10​

Answer 1

Step-by-step explanation:

)Option (c) Using Basic Remainder theorem. 10/3 gives a remainder of 1. 2) Option (c) First write all the numbers in base 10. 127 in base 8 = 7×1 + 2×8 + 1×82= 87 in base 10 12 in base 6 = 2×1+ 1×6= 8 in base 10. 3) Option (c) Converting base 2 to base 10 (11100)2=0+0+22+23+24=28. 4) Option (e)