Question

BASIS of first law of reflection in which angle of reflection is equal to angle of reflection

Answer 1

Law of Reflection:-

The law of reflection governs the reflection of light-rays off smooth conducting surfaces, such as polished metal or metal-coated glass mirrors.

Consider a light-ray incident on a plane mirror, as shown in Fig. 56. The law of reflection states that the incident ray, the reflected ray, and the normal to the surface of the mirror all lie in the same plane. Furthermore, the angle of reflection is equal to the angle of incidence .

Answer 2

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☯☯☯☯☯➡➡➡➡➡➡

The basis Of this law is

➡➡➡➡Light always take quickest path when travelling .

Now see

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$\huge\red{Reason}$

$<b>$ If we take a surface BC and two poles A and B . Always remeber light take quickest path ever.

In the figure if light from A strike on point O then i would be reflect to D . Because the quickest path to this points on the surface is AO . Now when it reflect these both the triangle ( triangle ABO and triangle DOC ) are congruent So the angle x And y are also equal and line OS is perpendicular line because it is normal line so the and i and r also equal .

Hence Proved ☺☺☺☯☯➡➡

$\underline{Thanks}$