Question

Basit's father is 26 years younger than Basit's grandmother and 29 years older than Basit. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answer 1

Answer:

Let age of Baichung's father age be x years

∴ Baichung's age and his grandfather's age ⇒(x−29) and (x+26) yrs respectively.

As per the question, Sum of ages of 3 people =135 years

∴x+x−29+x+26=135

3x−3=135

Transpose 3 to RHS, we will get,

3x=138

Divides both sides by 3, we will get

x=

3

138

⇒x=46

Baichung's father age =x=46 years

Baichung's age =x−29=46−29=17 years

Baichung's grandfather's age =x+26=46+26=72 years

Step-by-step explanation:

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Answer 2

$\huge\underbrace\mathcal\pink{anSwer}$

Let the present age of Basit = x

Then his Father's age = x + 29

Then Basit's grandmother age = (x+29) + 26

According to the question,

• x + (x+29) + (x+29)+26 = 135
• x + x + x + 29 + 29 + 26 = 135
• 3x + 84 = 135
• 3x = 135-84
• 3x = 51
• x = 51÷3
• x = 17

present age of Basit = x

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 17 years.

his Father's age = x + 29

⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀= 17 + 29

⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀= 46 years

Basit's grandmother age = (x+29) + 26

⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀= 17 + 29 + 26

⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀= 72 years.