Question

batao koi..........​

Answer 1

Step-by-step explanation:

MULTIPLYING AND DIVIDING THE EQUATION BY cos²x

WE GET .. INTEGRATION FROM 0 to π/2

$\frac{ { \sec}^{2}x.dx }{4 {tan}^{2}x + 5}$

PUTTING tanx = t

DIFFERENTIATING... sec²x.dx=dt

dx= dt/sec²x

WE GET I

$\frac{dt}{ {(2t)}^{2} + { \sqrt{5} }^{2} } \\ = > \frac{1}{2 \sqrt{5} } {tan}^{ - 1} \frac{2t}{ \sqrt{5} } \\ = > \frac{1}{2 \sqrt{5} } {tan}^{ - 1} \frac{2tanx}{ \sqrt{5} } \binom{ \frac{\pi}{2} }{0}$

HOPE YOU CAN SOLVE FURTHER BY PUTTING LIMITS

THANKS AND MARK ME AS BRAINLIEST.