Question

batsman scored 40% of his total runs by sixes 16% of his runs by fours and the rest by singles if he scored 33 runs by singles how many runs did he scored by sixes​

Answer 1

Answer :-

Batsman scored 30 runs by sixes.

Explanation :-

Let the total runs scored be 'x'

Batsman scored 40 % of his total runs by sixes

Runs scored by sixes = 40 % of x = 40/100 * x = 10x/25

Batsman scored 16 % of his runs by fours

Runs scored by fours = 16 % of x = 16/100 * x = 4x/25

Runs scored by singles = 33

⇒ Total runs scored - (Runs scored by sixes + Runs scored by fours) = 33

⇒ x - (10x/25 + 4x/25) = 33

⇒ x - {(10x + 4x)/25} = 33

⇒ x - (14x/25) = 33

⇒ (25x - 14x)/25 = 33

⇒ 11x/25 = 33

⇒ x/25 = 33/11

⇒ x/25 = 3

⇒ x = 3 * 25

⇒ x = 75

Runs scored by sixes = 10x/25 = 10(75)/25 = 750/25 = 30

∴ Batsman scored 30 runs by sixes.

Answer 2

Answer:

Step-by-step explanation:

Given :-

Runs % scored by sixes = 40 %

Runs % scored by fours = 16 %

Runs scored by singles = 33 Runs

To Find :-

Number of runs scored by sixes

Solution :-

Let the total runs scored be x.

According to The Question.

Sixes % = 40 % = $\frac{40}{y}\times x$ = $\frac{10x}{25}$

Fours % = 16 % = $\frac{4}{100}\times x$ = $\frac{4x}{25}$

Total runs scored - (Runs scored by sixes + Runs scored by fours) = 33

$\implies x -(\frac{10x}{25}+\frac{4x}{25})=33$

$\implies x-[\frac{(10x+4x)}{25}]=33$

$\implies x-(\frac{14x}{25})=33$

$\implies \frac{(25x-14x)}{25}=33$

$\implies \frac{11x}{25}=33$

$\implies \frac{x}{25}=3$

$\implies x=3\times25=75$

Number of runs scored by sixes = $\frac{10x}{25}$ = $\frac{10(75)}{25}$ = $\frac{750}{25}$ = 30.