Question

battery of 10 volts is connected in a circuit with 3 ohm 4 ohm 6 ohms connected in series how much current flow through a 6 ohm resistor

Answer 1

Given:-

R1 = 4 ohm

R2 = 6 ohm

R3 = 12 ohm

Rs = 2 ohm (Series resistor)

Potential difference, V= 6v

Let the resistance of all three resistors which are connected in parallel be Rp

Then,

1/Rp = 1/R1 +1/R2 + 1/R3

1/Rp = 1/4 + 1/6 + 1/12

1/Rp = 6/12

or,Rp = 12/6 = 2 ohm

Let total resistance be Rt = Rp +Rs

Rt = 2 + 2 = 4ohm

a)So current,I in the main circuit will be V=IR

therefore, I = V/R = 6/4 = 1.5A which is total current.

b) Since in parallel the current will divided into three resistors connected in parallel.Let the current across all the three be I1 ,I2 and I3.

Now,

I1 = V/R1 (Since potential difference is same as they are connected in parallel)

I1 = 6/4 = 1.5A

Similarly,I2 = V/R2

I2 = 6/6 = 1A

and I3 = 6/12 = 0.5A

c). V across 2ohm resistor will be-

V = I*R ( I will be total current)

:. V = 1.5 * 2 = 3V

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Answer 2

given
R1=3ohm, R2=4ohm,R3 =6ohm
Rs=R1+R2+R3
Rs=3+4+6=13ohm
V=10V
I=V÷R
I=10÷6
I=5/3
I=1.66A
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