Physics, asked by vikasseb, 9 months ago

battery of e.m.f E and internal resistance ‘r’ is connected to an external resistance’ r’. The terminal potential difference of the battery is
(a) 2E (b) E (c) E/2 (d) E/3

Answers

Answered by saurabhaadi4
0

Answer:

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Explanation:

ANSWER

i=

r+nr

E

=

(n+1)r

E

Terminal difference of cell=V=E−ir=E−

nr+r

Er

⟹V=

nr+r

Enr

=

n+1

En

Ratio of V and E is

n+1

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