Question

Battery of potential V is connected across the capacitor of capicatance C during charging the energy loss by battery

Answer 1

Explanation:

During charging of a capacitor 50% of the energy supplied by the battery is lost and only 50% is stored.

Thus, energy from battery is W=qE

Energy stored in capacitor is U=

2

1

qE

Heat produced H= energy lost=W−U=qE−

2

1

qE=

2

1

qE

as capacitor 50 % charged so q=CE/2.

Thus, H=

2

1

(CE/2)E=

4

CE

2