Question

bax+by):
2. Solve using substitution method:
23x-17y+11=0 and 31x+13y-57=0
​

Answer 1

Answer:

x = 1

y = 2

Step-by-step explanation:

23x - 17 y + 11 = 0

can be written for x as,

$x = \frac{ 17y - 11}{23} \: \: \: \: \: \: \: \: \: (1)$

substituting value of x in 31x + 13y - 57 = 0

$31( \frac{17y - 11}{23} ) + 13y - 57 = 0 \\ \frac{527y - 341}{23} + 13y - 57 = 0 \\ \frac{527y - 341 + 299y - 1311}{23} = 0 \\ \frac{826y - 1652}{23} = 0 \\ 826y - 1652 = 0 \\ y = \frac{1652}{826} \\ y = 2$

now put the value of y in (1)

$x = \frac{17(2) - 11}{23} \\ x = \frac{34 - 11}{23} \\ x = \frac{23}{23} \\ x = 1$

Therefore,

Therefore,x = 1 & y = 2