Question

Bay of bengal has 1.9 ppm of lithium ions what is the molarity of Li+ ions​

Answer 1

Answer:

2.7*10^-4

Explanation:

1.89 ppm of lithium ions corresponds to 1.89 g of lithium in 1000000 g of solvent.

Thus, 1 kg or 1000 g of solvent will contain 1.89×10  

−3

 g of  lithium.  

This corresponds to  

7

1.89×10  

−3

 

​  

=2.7×10  

−4

 mol of lithium.

Molality(m)=  

Mass of solvent (in kg)

Moles of lithium

​  

=  

1

2.7×10  

−4

 

​  

=2.7×10  

−4

m