Question

BB+6+AAA=_____find bb and aaa value

Answer 1

AB in digits =  (10 * A) + B 
BBB in digits = 100*B + 10*B + B = 111*B

A*B*AB=BBB
A*B*(10*A + B)=111B
Dividing by B on both sides, we get
A * (10*A + B) = 111

111 can be expressed as  3 * 37 = 3 * (10 * 3 + 7)
A * (10 * A + B) = 3 * (10 * 3 + 7)

So
A=3
B=7

Hope this will help u....