Math, asked by shivaniverma1904, 2 months ago

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A dishonest seller uses 1100 grams
instead of 1000gm while purchasing and
uses 750 gm instead of 1000 gm while
selling. If he claims to sell at a profit of
10%, find his actual profit percentage (to
the nearest Integer)​

Answers

Answered by moshnetic
0

Answer:

47%

Step-by-step explanation:

                                          While Buying :

In the question it is given that the seller has bought 1100 grams instead of 1000 grams

So he is buying 1100 grams at the price of 1000 grams

Let's assume that he bought the 1100 grams for Rs. 1000

                                            While Selling :                                  

And he sells 750 grams instead of 1000 grams

So he is selling 750 grams at the price of 1000 grams

But he claims that he is selling at a profit of 8%

So Selling Price = Rs. 1000 + ( 8% of Rs. 1000 ) = Rs. 1080

                                            Calculation :

He has bought 1100 grams for Rs. 1000

He has sold 750 grams for Rs. 1000

So he has sold ( 750 / 750 ) grams for Rs. ( 1000 / 750 ) -> To find out the Selling Price of 1 gram

=> He has sold 1 gram for Rs. ( 4 / 3)

=> He will have sold ( 1 * 1100) grams for Rs. [ (4/3) * 1100 ] -> To find out the Selling Price of 1100 grams to equate Buying and Selling amounts

=> He will have sold 1100 grams for Rs. 4400 / 3

Now Cost Price of 1100 grams is Rs. 1000 and Selling Price of 1100 grams is Rs. 4400 / 3

=> Actual Profit amount = Selling Price - Cost Price

= Rs (4400/3) - Rs. 1000

= Rs. (4400/3) - Rs. ( 3000/3) -> Taking LCM and equating the denominators

= Rs.  ( 4400 - 3000 ) / 3

= Rs. 1400 / 3

Actual Profit percentage = (Actual Profit * 100 ) / Cost Price

= ( 140000/3 ) / ( 1000)

= ( 140/3)

= 46.66666.... %

= 47 %  (Rounded off to the nearest integer)

Therefore the actual profit percentage of the dishonest shopkeeper is 47%

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