Question

बबदं ूQ िा रेख PR चा मध्यबबदं ूआिे आणि PR = 10 सेमी असेि तर PQ = ककती

Answer 1

Given:

बबदं ूQ िा रेख PR चा मध्यबबदं ूआिे आणि PR = 10 सेमी असेि तर PQ = ककती

If the line Q is the center of PR and PR = 10 cm, then PQ = how much?

To find:

PQ

Solution:

We know that,

A midpoint of any line segment divides it into two line segments of equal lengths.

Q is given as the midpoint of the line segment PR

So, we get

PQ = QR . . . (1)

Now,

$PR = PQ + QR$

From (1), we get

$\implies PR = PQ + PQ$

$\implies PR = 2PQ$

On substituting PR = 10 cm, we get

$\implies 10 = 2PQ$

$\implies PQ = \frac{10}{2}$

$\implies \bold{PQ = 5\:cm}$

Thus, the length of PQ is → 5 cm.

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Also View:

In a right triangle PQR, ∠Q=90°. If PQ=20 cm and QR= 21 cm, then find the length of the side PR.

brainly.in/question/23173263

If point m is the midpoint of seg ab. if ab=8 then find the length of am

brainly.in/question/3098151

Answer 2

Answer:

Given:

बबदं ूQ िा रेख PR चा मध्यबबदं ूआिे आणि PR = 10 सेमी असेि तर PQ = ककती

If the line Q is the center of PR and PR = 10 cm, then PQ = how much?

Solution:

We know that,

A midpoint of any line segment divides it into two line segments of equal lengths.

Q is given as the midpoint of the line segment PR

So, we get

PQ = QR . . . (1)

Now,

PR = PQ + QRPR=PQ+QR

From (1), we get

\implies PR = PQ + PQ⟹PR=PQ+PQ

\implies PR = 2PQ⟹PR=2PQ

On substituting PR = 10 cm, we get

\implies 10 = 2PQ⟹10=2PQ

\implies PQ = \frac{10}{2}⟹PQ=

2

10

\implies \bold{PQ = 5\:cm}⟹PQ=5cm

Thus, the length of PQ is → 5 cm.

-----------------------------------------------------------------------------------------

Also View:

In a right triangle PQR, ∠Q=90°. If PQ=20 cm and QR= 21 cm, then find the length of the side PR.

brainly.in/question/23173263

If point m is the midpoint of seg ab. if ab=8 then find the length of am

brainly.in/question/3098151