Bc=10cm de=6cm area of tranglr bcf
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Answer:
In ∆ABC,
A(∆ABC)= 15sq.cm,
Side BC is a base of the triangle and h is a height of a triangle.
BC=10cm, AC=6cm
A(∆ABC)= 1/2 base × height
15 = 1/2 × BC × h
15 = 1/2 × 10 × h
15 = 5 × h
h = 15/5
h = 3cm
In ∆DBC, angle BDC = 90°
BC=10cm, DC=6cm and BD=k
By Pythagoras theorem,
Hypt²= side² + side²
BC²= BD² + DC²
10²= k² + 6²
100 = k² + 36
100 - 36 = k²
k² = 64
taking squareroot,
k = 8cm
Step-by-step explanation:
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