Question

BC =12cm and BD = 3cm and the area ABC =80sq cm what is BD :DC

Answer 1

Answer:

Since we have given that

BC=12

BD=3

DC=BC-BD=12-3=9

So, BD:DC=3:9=1:3

So, we can let

BD=x and DC=3x

Now,

$\frac{\Delta ABD}{\Delta ADC}=\frac{\frac{1}{2}\times x\times h}{\frac{1}{2}\times 3x\times h}=\frac{1}{3}$

So,

3ABD=ADC\\

Now,

$</p><p>\Delta ABD+\Delta ADC=\Delta ABC\frac{\Delta ADC}{3}+\Delta ADC=\Delta ABC\frac{4\Delta ADC}{3}=80\Delta ADC=60\text{ square cm}</p><p>$

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