Question

BC=12cm BD =3cm area of triangle ABC=80sq.cm. Find the area of triangle ADC and the triangle ABD​

Answer 1

Step-by-step explanation:

आ हहWhat Should Be Added to (-7)/12 to Get 3/8? - Mathematics

∴ - 7 12 + x = 3 8.

⇒ x = 3 8 - - 7 12.

= 9 24 + 14 24.

= 9 + 14 24 = 23 24.

Answer 2

Answer:

The area of Δ ADC= 60 square cm.

Explanation:

Since we have given that

BC=12

BD=3

DC=BC-BD=12-3=9

So, BD:DC=3:9=1:3

So, we can let

BD=x and DC=3x

Now,

\frac{\Delta ABD}{\Delta ADC}=\frac{\frac{1}{2}\times x\times h}{\frac{1}{2}\times 3x\times h}=\frac{1}{3}

ΔADC

ΔABD

=

2

1

×3x×h

2

1

×x×h

=

3

1

So,

\begin{gathered}3ABD=ADC\\\end{gathered}

3ABD=ADC

Now,

\begin{gathered}\Delta ABD+\Delta ADC=\Delta ABC\\\\\frac{\Delta ADC}{3}+\Delta ADC=\Delta ABC\\\\\frac{4\Delta ADC}{3}=80\\\\\Delta ADC=60\text{ square cm}\end{gathered}

ΔABD+ΔADC=ΔABC

3

ΔADC

+ΔADC=ΔABC

3

4ΔADC

=80

ΔADC=60 square cm