bc(a²+1) +a(b2+c²) factorise
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Answered by
1
Answer:
your answer
Step-by-step explanation:
ab(a²+b²-c²) -bc(c²-a²-b²) +ca(a²+b²-c²)
ab(a²+b²-c²) +bc(-c²+a²+b²) +ca(a²+b²-c²)
ab(a²+b²-c²) +bc(a²+b²-c²) +ca(a²+b²-c²)
(a²+b²-c²)(ab+bc+ca)
Or,
===========================
{a+(b-c)(b+c)} [ab +bc+ca]
Answered by
3
Factorise : (a² – b²) c + (b² – c²)a
=(a² – b²) c + (b² – c²) a
= a²c – b²c + ab² – ac²
= a²c – ac² + ab² – b²c
= ac (a – c) + b² (a – c)
= (a – c) (ac + b²).
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