bc, ad and ae are tangents to the circle, if ab = 12 cm, find the perimeter of triangle abc
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20
From the figure,
AD=AE(since they are tangents to the circle)..(1)
LET THE POINT AT WHERE BC CONTACTS THE CIRCLE BE N
CE=CN .......(2)
and BD=BN......(3)
Therefore perimeter of ABC
AB+BN+AC+CN=AB+BD+AC+CE(from(2)and(3))
AD+AE=2(AD)(from(1))
2(12)=24cm
AD=AE(since they are tangents to the circle)..(1)
LET THE POINT AT WHERE BC CONTACTS THE CIRCLE BE N
CE=CN .......(2)
and BD=BN......(3)
Therefore perimeter of ABC
AB+BN+AC+CN=AB+BD+AC+CE(from(2)and(3))
AD+AE=2(AD)(from(1))
2(12)=24cm
Answered by
3
Perimeter of triangle ABC = 24 cm if bc, ad and ae are tangents to the circle, & ab = 12 cm
Step-by-step explanation:
Perimeter of triangle ABC
= AB + BC + AC
= (AD - BD) + BC + (AE - CE)
Let say BC touches circle at P
= (AD - BD) + (BP + CP) + ( AE - CE)
AE & AD are tangent from A on same circle
hence AD = AE = 12
BP = BD Tangent from B
CP = CE Tangent from C
Perimeter = ( 12 - BP) + ( BP + CP) + (12 - CP)
= 24
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