Question

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Q7. What is the perpendicular distance of the point (3,-4) from x-axis?
Q8. Write the coordinate of the point(s) which is on x- axis and at a distance of 5 units from y-axis.
09. Write the equation of the line which is parallel to y-axis and passes through the point (-1,2).
Q10. Find the value of a if (-1,1) is a solution of the equation 3x - ay = 5.
Q11. Express 0.36..... in the form of p/q where p and q are integers and q = 0.
2M X3
Q12, In which quadrant or on which axis do the following points lie ?
(-3, 4), (0,-2), (1,-1) and (-2,-2).​

Answer 1

Answer:

Step-by-step explanation:

Q7

the perpendicular distance of the point (3,-4) from x-axis  =  4

as this point will be (3 , 0)

Distance = √(3 - 3)²  + (-4-0)² = √0 + 16 = √16 = 4

Q8

the coordinate of the point(s) which is on x- axis and at a distance of 5 units from y-axis  = (5 , 0)  or (-5 , 0)

Q9  the equation of the line which is parallel to y-axis  

x  = c

passes through the point (-1,2).

=> -1 = c

=> x = - 1

=> x + 1 = 0

x + 1 = 0 is the equation of the line which is parallel to y-axis and passes through the point (-1,2).    

Q10

3x - ay = 5.

3(-1) - a(1) = 5

=> a = -8

value of a is - 8 if (-1,1) is a solution of the equation 3x - ay = 5

Q11  not clear

3 possibilities :

0.36   = 36/100  = 9/25

X = 0.3666666

10X = 3.66666666

100X = 36.66666666

90X = 33

=> X = 33/90 = 11/30

=> 0.3666666.... = 11/30

X = 0.3636363636

100X = 36.363636

99X = 36

=> X = 36/99 = 4/11

=> 0.363636.... = 4/11

Q 12

(-3, 4)  - 2nd

(0,-2)  Y axis

(1,-1)   4th

(-2,-2)  3rd