BC is a diameter of the circle and angle CAD=65° then find Angle BCD
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12
Answer:
angle is 25°
Step-by-step explanation:
BC is a diameter of a circle .
∴ ∠BAC = 90° ( Angle in semicircle)
⇒∠BAD + ∠DAC = ∠BAC ⇒90°
⇒∠BAD +65 = 90°
⇒∠BAd = 25°
by angles in same segment (i.e. ∠BAD and ∠BCD have same line segment BD)
∴∠BAD = ∠BCD
∴∠BCD =25°
I HOPE IT WILL HELP YOU!
Answered by
0
Answer:
25° I hope It may help you
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