BC is a diameter of the circle and
८BAO = 60°. Then ८ADC is equal to
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In ΔAOB,
∠OBA = ∠BAO
[angles opposite to equal sides are equal]
∠OBA = 60° [∴ ∠BAO = 60°, given]
∠ABC=∠ADC
[angles in the same segment AC are equal]
∠ADC = 60°
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