Math, asked by lucky2314A, 8 months ago

BC is a tower, B is its base. A is a point on a horizontal line passing through B, the
angle of elevetion of C from A is 60° From another point Don AB, the angle of
elevation is found to be 30°, then BD=​​

Answers

Answered by 1324amardeep
8

Hope ,this might help you.

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Answered by RvChaudharY50
35

Given :-

  • BC is a tower with B is its base. = Let height = h units.
  • A is a point on a horizontal line passing through B.
  • The angle of elevetion of C from A is 60° = CAB.
  • From another point D on AB, the angle of elevation is found to be 30° = CDB .

To Find :-

  • BD = ?

Solution :-

in Right ∆CBA ,

→ Tan60° = Perpendicular / Base

→ Tan60° = h / BA

→ √3 = h/BA

h = √3BA . ----------- (1)

Similarly,

in Right ∆CBD ,

→ Tan30° = Perpendicular / Base

→ Tan30° = h / BD

→ (1/√3) = h/BD

→ √3h = BD .

h = (BD/√3). -------------- (2)

From (1) and (2) , we get,

(BD/√3) = √3BA

→ BD = √3 * (√3BA)

BD = 3BA. (Ans.)

Hence, Length of BD is 3 times to the Length BA.

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