BCDE is a cyclic quad. CB and DE are produced to meet at A
Prove that triangle ACD///AEB
Show THAT AE.CD=AE.AD
---------- ------------
EB AB
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Answer:
Step-by-step explanation:
Considering triangle AEB and ACD
Angle A = Angle A (common)
Angle E = Angle D (corresponding )
Therefore triangle AEB is similar to triangle ACD
AE * CD = AE * AD (Corresponding sides of similar triangle is equal)
Not completely sure about the answer So dont expect it to be completely correct
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