BCDE is a cyclic quadrilateral
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Answer:35^0
Step-by-step explanation:In given figure ABCD is a cyclic quadrilateral.
We know that, sum of the opposite angles in a cyclic quadrilateral is 180
∘
So, ∠BCD + ∠BAD = 180
∘
⇒ 125
∘
+ ∠BAD = 180
∘
⇒ ∠BAD = 180
∘
- 125
∘
∴ ∠BAD = 55
∘
---- (1)
Since, ∠ABD is an angle in semi-circle.
∴ ∠ABD = 90
∘
--- (2)
In △ABD,
∠ADB + ∠ABD + ∠BAD = 180
∘
∠ADB + 90
∘
+ 55
∘
= 180
∘
(From 1 and 2)
∴ ∠ADB = 35
∘
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