Chemistry, asked by aliyaf301, 3 months ago

BCl3 structure of electron deficient compounds

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Answered by pranav3869
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Answer:

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Explanation:

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Answered by kalivyasapalepu99
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BCl3 is an electron-deficient compound. As boron has three valence electrons, it forms 3 single bonds with chlorine, In total the boron atom gives 6 electrons in the outermost shell. It still lacks 2 electrons to complete its octet.

Boron trichloride is a molecule that can be industrially produced by chlorinating boron oxide and carbon directly at 501°C.

B2O3    +    3C    +    3Cl2     ——–>    2BCl3    +    3CO

Corresponding trihalides of boron are produced during the reaction of boron with halogens.

Uses of BCl3 are immense. Boron trichloride is used in refining alloys of aluminum, zinc, magnesium, and copper.

The production of elemental boron needs BCl3 as a starting element.

The synthesis of organic compounds also involves this molecule. It is used as a reagent for cleaving C-O bonds in ethers.

Boron trichloride is also used in the manufacturing of electrical resistors, in the field of high energy fuels and rocket propellants.

First of all, we need to calculate the total valence electrons of this molecule,

B = 3

C l= 7

3Cl = 7*3=21

So, total= 21+3= 24

Now, boron is less electronegative, which makes it the central atom. We need to draw a skeletal structure with single bonds only.

Out of 24 valence electrons, 6 electrons were used to make the single bonds in the skeleton. Thus, we are left with 18 electrons, which we need to distribute among the Cl atoms.

Each Cl atom will now have 6 electrons or in other words, 3 lone pairs on each Cl atom.

Lastly, we need to check if all the atoms are fulling the octet rule. We can see from the following image that the octet rule is fulfilled by all atoms.

Now, as per the octet rule, in order to complete its octet boron needs another 6 electrons in its outermost shell. So it shares 3 single bonds with chlorine in order to gain stability.

On the other hand, chlorine needs another one electron to complete its octet. Thus chlorine also shares a bond with boron’s electrons to fulfill the octet rule.

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