Question

BCT CA = 445 any two
s
- 9>3 the lengt
i. The th
CATAB-st3
=874
9
given sid
sem , 6cm and 6cm​

Answer 1

Answer:

4.5=9∗0.5,42=14∗3,3.5=14∗0.25

Now,

149

= 14∗0.59∗0.5

= 14∗3

9∗3

=

14∗0.25

9∗0.25

⇒

14

9

=

7

4.5

=

42

27

=

3.5

2.25