Question

BD and CE are altitudes of triangle ABC such that BD = CE. Prove that CD = BE. Will mark branliest
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Answer 1

Answer:

answer is described in details in the explanation section.

Step-by-step explanation:

now comparing triangle BCE with triangle CBD

                       we know  angle E = angle D = 90 degree (given in question)

                                                BD = CE  (given in question)

                     BC is the common side which is shared by both the triangles

Thus, both the triangle BCE and CBD are Equilateral triangle.

So, BE=CD (proved)

Answer 2

Answer:

consider triangle BEC and triangle CDB

CE=BD (given)

angle BEC=angle CDB=90°

BC=BC (common side)

by RHS Congurency , BEC≈CDB

by cpct, BE=CD

hence, proved