BD and CE are the altitudes of ∆ABC and they are equal in length. (a) is ∆CBD congruent∆BCE? if so, mention the three pairs of equal parts in the two triangles. (b) is angle DCB = angle EBC? why or why not?
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In triangle CBD and triangle BCE
CE=BD(given)
Angle CEB = angle BDC(both 90degree)
BC=BC(common)
Therefore triangle ECB is congruent to triangle DBC
Therefore angle EBC=angle DCB (C.P.C.T)
CE=BD(given)
Angle CEB = angle BDC(both 90degree)
BC=BC(common)
Therefore triangle ECB is congruent to triangle DBC
Therefore angle EBC=angle DCB (C.P.C.T)
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