Math, asked by varshasahu3612, 4 months ago

BD and CE are the altitudes of triangles ABC and they are equal in length. (a) is triangle CBD congruent to triangle BCE? if so mention the three pairs of equal parts in the two triangles. (b) is angle DCB= angle EBC? why or why not.​

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Answered by momdadsneha6
0

Answer:

Answer:

The required probability is 1 .

Step-by-step explanation:

In any event , the sum of P(A) and P'(A) is always 1 .

Here , in a cricket match , the batswoman hits a boundary 25 times out of the 60 balls she plays .

The total number of balls ( Sample Space ) 60

Favourable Cases ( The no of times she hit a boundary ) > 25

Unfavourable Cases > 35

Probability that she hit a boundary > 25/60

Probability that she didn't hit a boundary > 35/60

Probability that she hit a boundary + Probability that she didn't hit a boundary

> 25/60 + 35/60

> 60/60

> 1

Additional Information :

\begin{gathered} \boxed {\begin{minipage}{9.2 cm}\\ \dag \: \underline{\Large\bf Formulas\:of\:Statistics} \\ \\ \bigstar \: \underline{\rm Mean:} \\ \\ \bullet\sf M=\dfrac {\Sigma x}{n} \\ \bullet\sf M=a+\dfrac {\Sigma fy}{\Sigma f} \\ \\ \bullet\sf M=A +\dfrac {\Sigma fy^i}{\Sigma f}\times c \\ \\ \bigstar \: \underline{\rm Median :} \\ \\ \bullet\sf M_d=\dfrac {n+1}{2} \:\left[\because n\:is\:odd\:number\right] \\ \bullet\sf M_d=\dfrac {1}{2}\left (\dfrac {n}{2}+\dfrac {n}{2}+1\right)\:\left[\because n\:is\:even\:number\right] \\ \\ \bullet\sf M_d=l+\dfrac {m-c}{f}\times i \\ \\ \bigstar \: {\boxed{\sf M_0=3M_d-2M}}\end {minipage}} \end{gathered}

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