Question

BD and CE are two altitude of a triangle ABC such that BD=CE prove that triangle ABC is isosceles

Answer 1

This is the answer of your question

Answer 2

Answer:

The proof is explained step-wise below :

Step-by-step explanation:

For better understanding of the solution, see the attached figure :

In ΔABD and ΔACE,

∠ADB = ∠AEC = 90°

∠BAD = ∠CAE  ( Common Angle )

BD = CE (Given)

By AAS postulate of congruency of triangles,

ΔABD ≅ ΔACE

Now, Corresponding parts of congruent triangles are equal

⇒ AB = AC

Hence Proved.