BD is a diagonal of a quadrilateral ABCD in which AM / BD and CN / BD. find area of a quadrilateral ABCD, if BD =40, AM = 20 and CN = 15.
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ar(quad. ABCD)=ar(△ABD)+ar(△BCD)
ar(quad. ABCD)=
2
1
(BD×AM)+
2
1
(BD×CN)
ar(quad. ABCD)=
2
1
BD×(AM+CN)
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