BD is a diameter of circle O. If mABC=30, what is the mDBA
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Question:
DB is a diameter of circle O. If mACB = 30°, what is the mDBA?
(a) 30° (b) 50° (c) 60° (d) 70° (e)90º
Solution:
(Angle subtended by the diameter is 90º)
∠DAB = 90º
(angles in a circle formed by the same arc are equal)
∠ ADB = ∠ACB
∠ ADB = 30º
(Sum of angles in a triangle is 180º)
∠DBA = 180 - 90 - 30
∠DBA = 60º
Answer: (c) ∠DBA = 60º
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Answer: it's just 60 believe me
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