BD is one of the diagonals of quadrilateral ABCD if AL perpendicular BD and CM perpendicular BD , show that ar(ABCD)=1/2×BD×(AL+CM)
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Hello Mate!
Given : AL and CM are perpendiculars on diagonal BD.
To prove : ar(ABCD) = ½ BD( AL + CM )
Proof : ar(∆ABD) = ½ × AL × BD
ar(∆BCD) = ½ × CM × BD
ar(ABCD) = ar(∆ABD) + ar(∆BCD)
ar(ABCD) = ½ × AL × BD + ½ × CM × BD
ar(ABCD) = ½ BD ( AL + CM )
Hence Proved
Have great future ahead!
Given : AL and CM are perpendiculars on diagonal BD.
To prove : ar(ABCD) = ½ BD( AL + CM )
Proof : ar(∆ABD) = ½ × AL × BD
ar(∆BCD) = ½ × CM × BD
ar(ABCD) = ar(∆ABD) + ar(∆BCD)
ar(ABCD) = ½ × AL × BD + ½ × CM × BD
ar(ABCD) = ½ BD ( AL + CM )
Hence Proved
Have great future ahead!
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Anonymous:
Superb answer :)
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