BD is the bisector of angle ABC, DP Ʇ AB and DQ Ʇ BC, DP=
DQ, prove that BP= BQ ( Hint : angle bisector theorem)
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BD 1 AC. If DP I AB and DQ 1 BC then prove that (a) DQ2 = DP.QC (b) DP2 = DQ: AP.
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