Question

BD is the median of ∆ABC.'F' is the point on AB such that CF intersects BD at E and BE=ED.if BF=5 cm then AB=??? ​

Answer 1

$\fbox{\fbox{\fbox{\fbox{ANSWER IS GIVEN BY STEP BY STEP EXPLANATION}}}}$

==>In a triangle ABC, BD is a median of a triangle.

==>And F is a point on AB such that CF intersects BD at E.

==>Also given BE=ED,BF=5cm.

==>Let G is a point on EC then FE=EG.

==>Join G and D and G and B, D and F.

==>∴ BGDF is a parallelogram.

==>BF=GD=5cm

==>GD∣∣AF then AF=10cm

==>Now, BA=BF+AF=5+10=15cm