Question

BE = 2.1 cm
BC = 4.2 cm
find DE.
EXERCISE - 8.2
1. In the given figure, ZADE = ZB
(i) Show that AABC~AADE
(ii) If AD=3.8 cm, AE = 3.6cm​

Answer 1

ANSWER.

In ΔADE and ΔABC, ∠ADE = ∠ABC (given)

∠A = ∠A (common)

ΔADE ~ ΔABC (AA similarity)

⇒\frac{AD}{AB} = \frac{DE}{BC} = \frac{AE}{AC} [Corresponding sides of similar △'s are proportional]

⇒ \frac{AD}{AB} = \frac{DE}{BC}

⇒ 3.83.6 + 2.1 = \frac{DE}{4.2}

⇒ 3.85.7 = \frac{DE}{4.2}

⇒ 23 = \frac{DE}{4.2}

⇒ DE = 2.8 cm

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Answer 2

Refer The Attachment ⬆️

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