Question

Be a1,a2...an so a1*a2*...*an=1
show that:


(1+a1)(1+a2)...(1+an)_>2^n





I got to

(1+a1)(1+a2)...(1+an)_ 2^n


but if x>y

and y z

it can be either

x>z>y

or

z>x>y


so how do i proceed?

Answer 1

Answer:

(1+a1)(1+a2)...(1+an)_>2^n

I got to

(1+a1)(1+a2)...(1+an)_ 2^n

but if x>y

and y z

it can be either

x>z>y

or

z>x>y

so how do i proceed