Question

BE ⊥AC and ∠ABD = (3x)° ,∠DBE = (x – 10)° . Find ∠DBC

Answer 1

Answer:

DBE = x - 10 + 90

so, 3x + x - 10 = 90

4x - 10 = 90

4x - 10 + 10 = 90 + 10

4x = 100

4x / 4 = 100 / 4

x = 25

so DBC = 25 - 10 + 90

15 + 90

115° ANSWER

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MARK AS BRAINLIEST

Answer 2

Step-by-step explanation:

∠ABD + ∠DBE = ∠EBA

(3x)° + (x – 10)° = 90°

4x - 10° = 90°

4x = 90° + 10°

4x = 100°

x = 100° ÷ 4

x = 25°

∠DBE = (x – 10)°

= 25° - 10°

= 15°

∠DBC = 90° + 15°

= 105°