Question

BE & CF are two equal altitudes of a triangle ABC . Using RHS Congruence rule , prove that the triangle ABC is Isosceles triangle



Note=> No figure is given ( draw it urself) ​

Answer 1

Answer:

Given: BE and CF are two equal altitudes of a triangle ABC. To Prove: ∆ABC is isosceles. ∴ ∠BCE = ∠CBF | C.P.C.T. ... Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC.

Answer 2

Given: BE and CF are two equal altitudes of a triangle ABC. To Prove: ∆ABC is isosceles. ∴ ∠BCE = ∠CBF | C.P.C.T. ... Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC