Question

BE and CF are altitudes of an isosceles ∆ABC in which AB=AC. Prove that BE=CF. ​

Answer 1

Step-by-step explanation:

In △ABE and △ACF,

we have ∠BEA=∠CFA (Each 90•)

∠A=∠A (Common angle)

AB=AC (Given)

∴△ABE≅△ACF (By SAS congruence criteria)

∴BE=CF [C.S.C.T]