Question

BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule,
prove that the triangle ABC is isosceles​

Answer 1

Answer:

By using RHS we can only prove that sum,If ∆ABC was a right angled triangle but u didn't mentioned that so here's ur answer!

Answer 2

Answer:

ΔABC is an isosceles tirangle

Step-by-step explanation:

In ΔBCE and ΔCBF,

∠E=∠F=90°

BC=CB [Hypotenuse]

BE=CE [Given]

By R.H.S congruence rule  ΔBCE≅ΔCBF

⇒∠B=∠C [By CPCT]

We know that a triangle two angles are equal then their opposite sides also equal.

So,AB=AC

Hence,ΔABC is an isosceles triangle.

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