Math, asked by siddiquizainabfaizi, 7 months ago

BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence
rule, prove that the triangle ABC is isosceles.
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Answers

Answered by HaCkIe44552211
1

Answer:

BE and CF are two equal altitudes of a triangle ABC. To Prove: ∆ABC is isosceles. ∴ ∠BCE = ∠CBF | C.P.C.T. ... Given: In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB.

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Answered by sam4915
2

Answer:

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