Question

BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence
rule, prove that the triangle ABC is isosceles.
P to show that​

Answer 1

Answer:

BE and CF are two equal altitudes of a triangle ABC. To Prove: ∆ABC is isosceles. ∴ ∠BCE = ∠CBF | C.P.C.T. ... Given: In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB.

Step-by-step explanation:

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Answer 2

Answer:

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