Question

BE and CF are two equal altitudes  of a triangle ABC.Using RHS congruence rule prove that the triangle ABC is isosceles.

Answer 1

it is ur answer. ........

Answer 2

Hello mate ^_^

____________________________/\_

Solution:

In ∆BEC and ∆CFB

BE=CF                (Given)

∠BEC=∠CFB              (Each given equal to 90°)

BC=CB                (Common)

Therefore, by RHS rule, ∆BEC≅∆CFB

It means that ∠C=∠B        (Corresponding parts of congruent triangles are equal)

⇒AB=AC                (In a triangle, sides opposite to equal angles are equal)

Therefore, ∆ABC is isosceles.

hope, this will help you.

Thank you______❤

_____________________________❤