Question

BE and CF are two equal altitudes of triangle ABC. Prove that triangle ABC is an isosceles triangle.​

Answer 1

Answer:

Given, BE and CF are two equal altitudes of a triangle ABC.

To Prove triangle ABC is isosceles.

angle BCE = angle CBF

C.P.C.T. Given, triangle ABC and triangle DBC are two isosceles triangle, on the same base BC vertices A and D are on the same side of BC.

Please like the answer.