Question

BE and CF are two equal altitudes of triangle ABC using RHS congruence rule prove that triangle ABC is isosceles​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

Given:

BE and CF are two altitudes of triangle ABC.

BE is also equal to CF.

To Prove:

∆ABC is an isosceles triangle i.e AB = AC

Proof: In ∆BCF and ∆CBE , we have

∠BFC = ∠CEB = 90°

BC = CB ( Common in both )

FC = EB ( Given , altitudes are equal )

So, ∆BCF ≅ ∆CBE , by RHS congruence rule.

∴ ∠FBC = ∠ECB ( By C.P.CT )

As we know that if two angles are equal then the sides opposite to that angles are also equal.

=> we got AB = AC

Hence, ∆ABC is an isosceles triangle.