Math, asked by siddarthhuded, 9 months ago

BE and
In the given figure
of AD
ABCD is a sua Square
'E is the midpoint
joined Prove that A BEC is
isosceles triangle
CE are
an​

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Answers

Answered by Joannaalex
7

Answer:

abcd is a square

e is the mid point

angle a=b=c=d=90°. reason angles of square r 90

construction join ed and eb

in ∆bec

angle b=c. each 90

therefore be =ec

hence ∆bec is an isoceles triangle

cuz when two sides of a triangle r congruent it is an isoceles triangle

or isoceles triangle theorem

hope it helps

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