BE and
In the given figure
of AD
ABCD is a sua Square
'E is the midpoint
joined Prove that A BEC is
isosceles triangle
CE are
an
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Answer:
abcd is a square
e is the mid point
angle a=b=c=d=90°. reason angles of square r 90
construction join ed and eb
in ∆bec
angle b=c. each 90
therefore be =ec
hence ∆bec is an isoceles triangle
cuz when two sides of a triangle r congruent it is an isoceles triangle
or isoceles triangle theorem
hope it helps
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