be fast to answer this guys
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2
>>>>>
2( cot^2 45 + sec^2 30) -6 ( tan^2 45 - cosec^2 60)
2[( 1 + ( 2/√3)^2] -6[(1 - (2/√3 )^ 2]
2( 1+ ) -6 (1- )
2()- 6( )
+
bami:
thnk u soo much for ur answer
Answered by
4
2[(1^2+(2/√3)- 6[(1^2-(2/√3)^2]
2(1+4/3)-6(1-4/3)
2(3+4/3)-6(3-4/3)
14/3+6/3
20/3
so option b is the correct answer
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