Math, asked by bami, 1 year ago

be fast to answer this guys

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Answered by BrainlyWarrior
2
\boxed{Hello} {Mate}<br />

\boxed{The}{(B)...} {Option ...} { Is ...} { correct... }<br />

\blue{Explanation}<br />>>>>>

2( cot^2 45 + sec^2 30) -6 ( tan^2 45 - cosec^2 60)

2[( 1^2 + ( 2/√3)^2] -6[(1^2 - (2/√3 )^ 2]

2( 1+ \frac{4}{3}) -6 (1- \frac{4}{3} )

2(\frac{3 + 4}{3})- 6( \frac{3 - 4}{3})

\frac{14}{3} + \frac{6}{3}

\frac{20}{3}

\huge{Be} { Brainly....}

bami: thnk u soo much for ur answer
BrainlyWarrior: wlcm dear
Answered by kaniya
4

2[(1^2+(2/√3)- 6[(1^2-(2/√3)^2]
2(1+4/3)-6(1-4/3)
2(3+4/3)-6(3-4/3)
14/3+6/3
20/3
so option b is the correct answer


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