Be given figure, ab, cd, pq are all perpendicular to bq and ab = 5, pq = 4, then cd=?
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Given : ab, cd, pq are all perpendicular to bd and ab = 5, pq = 4,
To Find : cd
Solution:
ΔPQD ≈ ΔABD
=> PQ/AB = QD/BD
ΔPQB ≈ ΔCDB
=> PQ/CD = BQ/BD
PQ/AB + PQ/CD = QD/BD + BQ/BD
=> PQ/AB + PQ/CD = (QD + BQ)/BD
=> PQ/AB + PQ/CD =BD/BD
=> PQ/AB + PQ/CD =1
=> 4/5 + 4/CD = 1
=> 4/CD = 1 - 4/5
=> 4/CD = 1/5
=> CD = 20
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